Pay attention to the application of particularity to general ideas.
12, b is bB 1 ⊥ y in b1,and a is AA 1⊥L, | bb 1 | = m/e, |
| am | = | aa 1 |-| bb 1 | = 2m/e,let ∠ baa 1 = θ,cosθ= | am |/| ab | = 2/4e = 1/2e = 65438。
So k=tanθ=√2.