(1/x 1+ 1/x2) divided by 2 = 2; 1/x1+1/x2 = 4 and then use Vieta's theorem; Two x 1, x2 have the following relationship: x1+x2 =-b/ax1x2 = c/a.

X 1+x2 = 8/3。 X 1 x2 = a/3。

1/x 1+ 1/x2=4。 Ordinary score; (x 1+x2)/x 1 x2 = 4, and the value of a is 2.