Add up to 5*4/2= 10 games. Each team played against other teams four times.
Let team a win x and draw y.
x+Y & lt； =4。
3X+Y=9。
Get:
x=3.y=0。
Team a's record is 3 wins, 0 draws 1 negative. Liu Jin 123
2) Suppose that the record of Team B is a total victory.
Then team b won all four games, 12 points.
As you can see, Team A lost to Team B 1 time and won with the other three teams.
It can be seen that Team C, Team D and Team E3 lost to Team A and Team B2. Win two games at most. There are six points at most.
So team a is qualified. Liu Jin 123
3) Assume that the record of Team B is 10. It's 3 wins 1 draw and 0 losses.
It can be seen that Team A only lost to Team B. That is to say, C, D and E all lost to Team A. Of the three teams, 1 drew with Team B 1 time, and the other two teams lost to Team B. ..
The highest score of team CDE3 is 2 wins 1 draw 1 negative. There are seven o'clock.
So team a is qualified. Liu Jin 123
4) The team with the highest score gets 9 points.
Because there is a situation of 1, if there are three teams of A, B and C with 9 points, 3 wins and 0 draws 1 negative.
That is, A only loses to B, B only loses to C, and C only loses to A .... Both d and e lost to ABC. This situation is possible,
At this time, because all three teams are 9 points. A may be unqualified.
Liu Jin 123