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In the second volume of the sixth grade, there is one exercise in each lesson of mathematics, and how to write the problem-solving on pages 19 and 20.
Ha ha! This question is really intriguing! I am a primary school graduate in 2009 ~ ~ ~ There is absolutely no problem ~ ~ ~ ~ The title is guaranteed to be correct ~ ~ ~ and the format is still standard ~ ~ ~ ~ Let me answer ~ ~ ~

I. 10× 10= 100 (square meter)

1.5×100 =150 (m3)

Answer: The building area is 100 m2, and the pool volume is 150 m3.

2.6×6=36 (square centimeter)

282.6÷36=7.85 cm

A: The height of this cylindrical machine part is 7.85 cm.

Three. 12.56÷3. 14=4 (m)

4÷2=2 (meter)

2×2×3. 14= 12.56 (m2)

12.56× 4.8 ÷ 3×1= 20.096 (m3)

0.2× 10=2 (m2)

20.096÷2= 10.048 (m)

Answer: It can be paved 10.048 meters long.

4.6×6÷2= 18 (square centimeter)

Answer: The sum of the two surface areas is 18 cm2 more than the original cone surface area.

V. 20÷2= 10 (cm)

10× 10×0.3=30 (cubic centimeter)

Solution: Let the height of conical iron block be x cm.

Judging from the meaning of the question, 3×3×x÷3=30.

9x÷3=30

3x=30

x= 10

Answer: The height of the tapered iron block is 10 cm.

Ouch. . . . . . It's hard for me to remember. . . It's boring without a thumbs up. At least I helped you. . . Thank you ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~