O is the midpoint of AC, and AB=2OF.

F is the midpoint of BC.

BF=FC，∠BAF=∠CEF，∠ABF=∠ECF

△BAF congruence△ △CEF

∴AB=CD=CE

(2) AB = BC, ∠ ABC = 60, ∴ ... are equilateral triangles.

∵AF is the center line of BC.

∴AF⊥BC

∴CF= 1,AF= root number 3.

S triangle OGF=S△BOC-S△OFc-S△BGF

= radical number 3/2- radical number 3/4- radical number 3/6

= root number 3/ 12

Where the area of the whole large regular triangle is the root number 3, △BOC is 1/2, △OFc is 1/4 and △BGF is 1/6.

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