I. Surface areas of three cylinders

1，3. 14× 1.5 2 = 7.065 cm2 7.065×2+3. 14× 1.5×2× 1 = 23.55 cm2。

2.3. 14× 1 ^ 2 = 3. 14 cm2+3. 14×04× 1×2× 1 = 12.56 cm2。

3.3. 14×0.5 2 = 0.785×2+3. 14×0.5×2× 1 = 4.7 1 cm2。

2. Combined surface area: The combined surface area is reduced to two bottom areas with a radius of 1m and two bottom areas with a radius of 0.5m, so

(23.55+ 12.56+4.7 1)-(3. 14×2+0.785×2)= 32.97 cm2。