Current location - Training Enrollment Network - Mathematics courses - Mathematics Tangshan volume
Mathematics Tangshan volume
Suppose X pieces of A-type handicrafts are produced, then 80-x pieces of B-type products are produced.

0.6x+ 1. 1(80-x)& lt; =69

0.9x+0.4(80-x)& lt; =52

The solution is 38

Because X is a natural number, X can only take 38, 39 and 40.

Scheme 1: produce 38 A-type handicrafts and 42 B-type handicrafts;

Scheme 2: produce 39 A-type handicrafts and 4 1 B-type handicrafts;

Scheme 3: make 40 A-type handicrafts and 40 B-type handicrafts;

Suppose X pieces of A-type handicrafts are produced, then 80-x pieces of B-type products are produced.

y=45x+50(80-x)

y=45x+4000-50x

y=-5x+4000

Because a < 0, from the nature of linear function, y decreases with the increase of x 。

Therefore, at 38

When x=38, the maximum value of y is =38 10/0.

Therefore, scheme 1 should be adopted.

y=(45+a)x+50(80-x)

=(a-5)x+4000

When a-5

Therefore, scheme 1 should be adopted.

When a-5 >; =0, that is, a> When =5, from the nature of linear function, y increases with the increase of x.

Option 3 should therefore be adopted.