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20 14 Jiujiang two-module mathematics
(1) Connect BC, and make the optical path diagram as shown in the figure.

(2) The incident angle and refraction angle of light at the interface of point B are I and R, respectively.

sini=AMR=22=45

Refractive index n=sinisinr

Get: sinr= 12.

The propagation time t of light in the ball

T=BCV=2R? cosθ2cn=63× 10-9(s)

(3) The exit angle β at point C is

sinrsinβ= 1n

Sin β = 22 β = 45。

∠COP=π-θ 1-∠BOC= 15

α+∠COP=β

Get α = 30.

Answer: (1) Complete the light path diagram as shown in the figure;

(2) The propagation time of light from point B to point C is 63×10-9 (s);

(3) 3) The angle α between CD and MN is 30.