= 1/(2^x-√2)+ 1/[(2/2^)-√2]
= 1/(2^x-√2)+2^x/(2-2^x*√2)
=√2/(2^x*√2-2)+2^x/(2-2^x*√2)
=√2/(2^x*√2-2)-2^x/(2^x*√2-2)
=(√2-2^x)/(2^x*√2-2)
=-(2^x-√2)/√2(2^x-√2)
=- 1/√2
=-√2/2
Sum of independent variables =1(x+1-x =1)
Sum of function values =-√2/2
s = f(-5)+f(-4)+……+f(0)+f( 1)+……+f(5)+f(6)
s = f(6)+f(5)+…+f( 1)+f(0)+…+f(-4)+f(-5)add。
2S =-√2/2-√2/2……-√2/2-√2/2……-√2/2-√2/2 =-6√2
S=-3√2