The seventh grade math class is in a hurry to reach the standard ~ ~ ~ ~ Thank you ~ ~ ~ ~ ~ Please ~ ~ ~ ~ Please help me with high IQ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ The first problem is that because A-B=5, A=B+5, so [2 (b+50+3b-2 *1]-[3 *1+2b-2 (b+50)] is equal to (2b+10). Equal to 5B+8-(-7) equals 5B+ 15 equals B+3. I don't understand where I am. My second question is that 5050 is 5050a = 5050 *-2 =-100/00 because it is from 1+. Ok. Give me TAT, which means multiply.