Because angle e = angle ACD = 90 degrees, angle EDB= = angle CDA,
Ad = BD, so all triangles EDB are equal to CDA. ..
So AC = be, BC = 2be, because the angle BCD=30 degrees.
Let be = x, then BC = 2x, CE = root 3X,
Cd = root 3X, AC = x,
The root of ad = 2 7x,
So the sine value of the angle CDA =AC/AD=X/2 root 7x = 2 times of 7.
Root number 7, cosine value of angle CDA = 2 of root number 3X/2/ 2 of root number 7X=7 = 7 of root number 2 1.