1)0.2 to the fifth power times 5 to the fifth power = (0.2 * 5) 5 = 1.

2) (4/3) 2 1 times 0.75 to 20.

=(4/3)^20*4/3*(3/4)^20

=(4/3*3/4)^20*4/3

=4/3

3)0.375 10 1 power (8/3)100th power.

=(3/8)^ 100*3/8*(8/3)^ 100

=(3/8*8/3)^ 100*3/8

=3/8

2。 It is known that t is a positive integer, which satisfies (the third power of t+ 1 times the second power of t) minus (the third power of t times the second power of t+ 1) = the sixth power of 3. Find the value of t

3^(t+ 1)*2^t-3^t*2^(t+ 1)=6^3

3^t*3*2^t-3^t*2^t*2=2^3*3^3

3^t*2^t=6^3

(3*2)^t=6^3

6^t=6^3

t=3

3。 Given the m power of 2 = 16 and the n power of 3 = 27, find the value of the algebraic expression (the m power of 4 times the n power of minus 0.25) plus the 2004 power of (m minus n).

2^m=2^4

m=4

3^n=3^3

n=3

4^m(- 1/4)^n+(m-n)^2004

=4^4*(- 1/4)^3+(4-3)^2004

=256*(- 1/64)= 1

=-4+ 1

=-3