x 1^3+8×x2+20
=(-3×x 1— 1)×x 1+8×x2+20
=—3(x 1^2+3×x 1+ 1)+8(x 1+x2)+23
Because x12+3× x1+1= 0, x1+x2 =-3;
therefore
Original formula =- 1.