(1) No.2 falls in Box No.2, so there are A33 (arrangement form, two 3s are in the upper right corner and the lower right corner respectively) cases, that is, there are six cases, and one * * * is A44 case, so the probability that 2 falls in 2 is 0.25.

(2) If only one card matches, such as the original sequence of boxes is 1 2 3 4, if only 1 matches, there are two situations: 1 3 4 2, 1 4 2 3. So there is only one match, which is 8/24; The cases where two numbers match are 1234 and 1243, so A42-* * has 12 cases, so it is impossible to have three matches, only 1 case has four matches. If none of them match, then there are three situations, and then the rest is calculated by yourself.