From realizing that you should stop to operating the brakes, the car moves in a straight line at a constant speed; The movement from braking to stopping can be considered as uniform deceleration movement.
The displacement of uniform motion is s1= 33.3 * 0.7 = 23.31m, and the displacement of uniform deceleration is S2 =134.2-23.31=10.89m.
According to the formula:
2as=v? -v0?
Get:
a=0-v? /2s=-33.3? /(2 * 1 10.89)=-5.0m/s?
( 1)
How long does it take to slow down to 0 t=0-v? /a=22. 17s
(2)
The average deceleration of the vehicle after deceleration = a *1s = 5.0m/s.
(3)
83=33.3t+ 1/2*5.0*t?
Solution:
T=2.2s (negative values are rounded off)
It takes 2.2s to taxi to 83m after braking.