From realizing that you should stop to operating the brakes, the car moves in a straight line at a constant speed; The movement from braking to stopping can be considered as uniform deceleration movement.

The displacement of uniform motion is s1= 33.3 * 0.7 = 23.31m, and the displacement of uniform deceleration is S2 =134.2-23.31=10.89m.

According to the formula:

2as=v？ -v0？

Get:

a=0-v？ /2s=-33.3？ /(2 * 1 10.89)=-5.0m/s？

( 1)

How long does it take to slow down to 0 t=0-v? /a=22. 17s

(2)

The average deceleration of the vehicle after deceleration = a *1s = 5.0m/s.

(3)

83=33.3t+ 1/2*5.0*t？

Solution:

T=2.2s (negative values are rounded off)

It takes 2.2s to taxi to 83m after braking.