1.
Determine how many two-digit numbers exist with the following properties: when this number is added with a number in which one digit and ten digits are reversed, the sum is 132.
2. examples.
A= 10x+y
B= 10y+x
A+B= 132
( 10x+y)+( 10y+x)= 1 1x+ 1 1y = 132
3. The solution can usually be solved by exhaustive method. Try it step by step with x= 1 etc.
One of my reference answers is X = 3 and Y = 9.