Linlin spent two-fifths of the money for the first time and 240 yuan for the second time. After spending a third of all the money, there is still 720 left. How much did it cost for the first time?

hello

Now that you have explained that this is a primary school math problem, try to explain it with arithmetic:

Now Linlin still has 720 yuan in his hand, which is two-thirds of that before he used the money for the second time (because he used one-third).

So Linlin divided the 720 yuan into two equal parts, each 360 yuan (=720/2,/is a divisor).

Linlin will understand, then the share I just spent should also be 360 yuan

She calculated that before I spent the second time, I had 720+360= 1080 yuan.

If I don't want 240 yuan, how much money do I have? The answer is 1080-240=840 yuan.

At this time, Linlin divided 840 yuan money into three equal parts according to the method just now: each 280 yuan (=840/3).

So Linlin has three copies left. How much should it cost to spend two? Because of each 280 yuan, the answer is 280*2=560 yuan.

I don't know if you understand. Welcome to ask questions ~