First of all, in 2008, the father's age was X, the mother's age was (80-x), the elder brother's age was Y, and the younger brother's age was (19-y).
According to the meaning of the question, the situation after three years is x+3=4*( 19-y+3).
(80-x)+3=3*(y+3)，
Solve it, x=4 1, y= 1 1,
That is, in 2008, the father's age was 4 1, the mother's age was 80-4 1 = 39, the elder brother's age was1= 8, and the younger brother's age was19-1=
Finally, suppose that the father is three times older than his brother in Z, and z+41= 3 * (11+z). If you solve it, you will get z=4.
That is, in 2008+4=20 12, my father was three times older than my brother.
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