When we first met, the two cars walked the whole distance, and Car A walked 90 kilometers.

At the second meeting, the two cars walked three full distances, so the car A walked 3*90 kilometers.

3 × 90km+50km =2 whole journeys.

So the distance between AB =(3 distance 90+50)÷2= 160 (km).

Solution 2:

Suppose that car B traveled X kilometers when they first met, then AB=x+90 (kilometers).

Distance series equation using line B * * *:

3x=50+x+90

Solution:

x=70

So AB =70+90= 160 (km) distance.

Solution 3:

Suppose the whole journey is x kilometers.

When we meet for the first time, the distance of line A is X-90) km, and the distance of line B is (X-90)km.

Their ratio is equal to their speed ratio of 90/(x-90) km.

Meeting again is equivalent to two cars driving two total distances each.

The distance of the second line is (90+50) kilometers,

The distance of Line A is (2x-90-50) kilometers.

The distance ratio between Party A and Party B means that the speed ratio is (2x-90-50)/(90+50).

Because both transmission ratios are speed ratios,

So the energy ratio is:

90/ X-90=(2X-90-50)/(90+50)

The simplification on the right is:

90/(x-90) = (x-70)/70 If it can be inferred that the numerator and denominator are equal, it is 90 = x-70 x = 160. You can also get x by solving the ratio. =X× 160. So x = 160.