The intersection point D is perpendicular to the X axis, the vertical foot is m, the intersection point C is perpendicular to the Y axis, and the vertical foot is n..

DM and CN intersect at point F.

Then △ ABO△ CDF

∴DF=2,CF= 1

The area of ∫ quadrilateral BCDE is five times that of △ABE.

∴(BC+AD)=5AE

∴DE=2AE

∴MO=2AO

The abscissa of point d is 2,

The abscissa of point C is 3.

The coordinate of the set point is (2, m)

The coordinate of point ∴c is (3, m-2)

∵C and d are both on the image of function y = k/X.

∴k=2m=3(m-2)

The solution is m = 6 and k = 12.