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Mathematical solution set q
1, method 1: when x =-2,8-2p+q = 0, -( 1). When x= 1, 2+p+q=0-(2)

Solutions (1) and (2), p=2, q=-4.

Method 2: -2, 1 is the equation 2x? +px+q=0,so -2+ 1=-p/2,-2* 1=q/2,

So, p=2 and q=-4.

2、A={x|x? -(a+ 1)x+a & lt; 0} B={x|x? -4x+3≤0}={x| 1≤x≤3} .x? -(a+ 1)x+a=0,x 1= 1,x2 = a。

If a< 1, then a = {x | a

If a> 1, then a = {x | 1

So the range of a is: 1≤a≤3.