1, method 1: when x =-2,8-2p+q = 0, -( 1). When x= 1, 2+p+q=0-(2)

Solutions (1) and (2), p=2, q=-4.

Method 2: -2, 1 is the equation 2x? +px+q=0，so -2+ 1=-p/2，-2* 1=q/2，

So, p=2 and q=-4.

2、A={x|x？ -(a+ 1)x+a & lt； 0} B={x|x？ -4x+3≤0}={x| 1≤x≤3} .x？ -(a+ 1)x+a=0，x 1= 1，x2 = a。

If a< 1, then a = {x | a

If a> 1, then a = {x | 1

So the range of a is: 1≤a≤3.