√6x+2y+2√3=0。

Let the distance d from the origin o to the straight line AB (that is, to y) be set,

Then, d = | (√ 6) * 0+2 * 0+2 √ 3 |/√ [2 2+(√ 6) 2]

d=2√3/√ 10。

D = √ 30/5。 -That's what you want.