Suppose car A has car X and car B has car Y, then there are:
45x+30y & lt; Or = 234 400x+280y
So x=5 y= 1.
x=4 y=2
X=3 y=4 (s)
That is to say, there are only two options: one car, five cars, 1 car or one car, four cars and two cars.