(2)FB = GB = mBg = 13.5kg×9.8N/kg = 132.3n； ?

pB = FBSB = GBSB = MB gsb = 132.3n(0.3m)2 = 1470 pa；

Answer: The pressure of object B on the horizontal ground is1470 Pa; ;

(3)∵pA = FASA = GASA = magsa =16kg× 9.8n/kg (0.2m) 2 = 3920pa;

∴ If the part with the mass of △m is vertically cut off from the right side of object B, and the cut-off part is superimposed on object A, and object B is still a cylinder with the same height and density, then the pressure of object B on the ground remains unchanged, which is1470 Pa; However, the pressure of object A on the ground will increase, and the stress area of the ground will remain unchanged, so the pressure of object A on the ground will increase, that is, it will be greater than 3920 Pa. Therefore, the pressure of object A on the ground is greater than that of object B, so the first option is "No".

If the part with the mass of △m is cut from the object A in the horizontal direction, and the cut part is superimposed on the object B, so that the pressure on the horizontal desktop is the same, then: pA? =pB？ (Horse? △m)gSA =(m b+△m)gSB； Namely: 16kg? △m(0.2m)2 = 13.5kg+△m(0.3m)2

Therefore: △ m = 6.923 kg.

Therefore, the second option is possible.

A: Option 2 is "Yes"; The interception mass △m is 6.923kg. ..