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Math problems in Grade Two are more difficult.
ef+gh+mn=8

∫ab is parallel to ef

Mn is connected in parallel with ac.

Quadrilateral Ampere is a parallelogram.

∴pe=ae ep=am

Gh is parallel to bc

Ab is parallel to ef

∴ Quadrilateral gbfp is a parallelogram

∴gb=pf

The same can be proved.

The quadrilateral hpnc is a parallelogram.

∴hc=pn

∵ equilateral triangle abc

∴∠a=∠b=∠c=60

∫ab is parallel to ef

Mn is connected in parallel with ac.

Gh is parallel to bc.

∴∠mgp=∠b=60

∠gmp=∠a=60

∴mg=gp

Similarly, it can be proved that eh = ph.

∴gp+hp+mp+ep+pf+pn=mg+eh+ae+am+gb+hc

∴EF+GH+MN=ab+ac=8