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A math application problem in grade three.
Assuming that the price per kilogram of apples should be reduced by n yuan, the equation is obtained according to the meaning of the question:

(3-n-2)×(200+n/0. 1×40)= 200+24

Solution: n 1=0.2

n2=0.3

It is verified that both schemes are reasonable. So 0.2 yuan or 0.3 yuan can reduce the price.

3-n is the unit price after the price reduction, and then the cost of 2 is deducted, which is the net profit per kilogram of apples.

N/0. 1 ×40: every time the price is reduced by 0. 1 yuan/kg, 40 kg can be sold every day. How many n/0. 1 0. 1.

Plus 200, it is the daily sales volume, multiplied by the net profit per kilogram of apples, it is the daily profit.

Namely, the profit target, the fixed cost of 200 yuan and 24 yuan.