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Solve the problem-solving process and answer of 20 1 1 Hubei college entrance examination literature and history mathematics 13.
The first space: according to m = LGA-LGA0 = LG (1000)-LG (0.001) = 3-(-3) = 6;
Second space: If the maximum amplitude is A 1 of grade 9 and A2 of grade 5, then LGA1-lga0 = LG (a1/a0) = 9, so a1/a0 =109; Similarly: A2/A0 =105; Then divide the two formulas by a1/a2 =104 =10000.