∫ The image of linear function y=-2x+2 intersects with X axis at point B, and intersects with Y axis at point C,
When x=0, y=2, when y=0, x= 1,
∴ The coordinates of point B are; (1, 0), the coordinates of point C are: (0,2),
∵AD⊥CD,
∴BO∥AD,
∴BOAD=BCAC=COCD,
AB = 2BC,
∴COCD=BOAD= 13,
∴DO=4,AD=3,
∴ The coordinates of point A are: (3, -4),
Substitute y=mx:
xy=m=3×(-4)=- 12,
The inverse ratio resolution function is: y=? 12x;
(2)S△APC = S△BPC+S△ABP = 12,
∴ 12×2×bp+ 12×bp×4= 12,
Solution: BP=4,
∴ The coordinates of point p are: (5,0),
Similarly, there is a point (-3,0) on the left side of the Y axis, so that the area of △APC is equal to 12.
To sum up, the coordinates of point P are (5,0) or (-3,0).