∫In Rt△ABC,AC? =AB? +BC?
∫In Rt△ACC 1,AC 1? =AC? +C 1C?
∴AC 1? =AB? +BC? +C 1C?
∴C 1C? =AC 1? -(AB? +BC? )
∴C 1C=√(AC 1? -AB? -BC? ))=√(3? -2? -2? )= 1
Rectangular ∴ surface area ABCD-a1b1c1s = 2 * ab * BC+2 * BC * c1c+2 * AC * c/kloc-.
=2*2*2+2*2* 1+2*2* 1=8+4+4= 16