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Mathematical answer analysis
Solution: Connect AC, then △ACC 1 is a right triangle.

∫In Rt△ABC,AC? =AB? +BC?

∫In Rt△ACC 1,AC 1? =AC? +C 1C?

∴AC 1? =AB? +BC? +C 1C?

∴C 1C? =AC 1? -(AB? +BC? )

∴C 1C=√(AC 1? -AB? -BC? ))=√(3? -2? -2? )= 1

Rectangular ∴ surface area ABCD-a1b1c1s = 2 * ab * BC+2 * BC * c1c+2 * AC * c/kloc-.

=2*2*2+2*2* 1+2*2* 1=8+4+4= 16