The problem of pouring wine in interesting mathematics
This problem is the same as sharing wine among four people. I told you that the landlord understood it himself. First, pour the first 3-ounce bottle of wine into a glass for A to drink. Then pour 3 taels into the glass, and there are 2 taels left in the first bottle for B to drink; Pour the three-ounce glass back into the first bottle, pour the second bottle into the glass, then pour the first bottle out of the glass, then pour the second bottle into the glass, and continue to pour the glass into the first bottle. At this time, because the first bottle has six ounces, only two ounces of wine glasses enter the first bottle, leaving 1 ounce of wine glasses for C to drink; The situation now is that the first bottle is full and the second bottle has 22 ounces left. Pour the first bottle of 32-ounce wine into the wine glass, the second bottle of 22-ounce wine into the first bottle, the first bottle of 32-ounce wine into the wine glass, the second bottle of 32-ounce wine into the second bottle, and the first bottle of 32-ounce wine into the wine glass, so that the first bottle of 1 ounce wine is reserved for D and the second bottle of 62-ounce wine. The following division is simple. Let the landlord think for himself.