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Application problems of buying a few and getting a few free in primary school mathematics
Examples of formulas for several problems in primary school mathematics;

1. actual unit price = original unit price × buy a few ÷ (buy a few+send a few)

2. Cheap money per piece = original unit price-actual unit price.

3. Actual total price = original unit price × number of purchases (buy several+send several) × number of purchases.

Or = purchase quantity ÷ (buy a few+send a few) × (original unit price × buy a few)

4. Actual purchase quantity = purchase quantity ÷ (buy a few+send a few) × buy a few.

5. How much money can you buy = total money ÷ actual unit price.

Or the total amount of money, the number of money bought × (buy a few+send a few)

1, Xiaoming buys pens, and each 5 yuan gets 4 pens 1, and Xiaoming buys 4 pens. How much cheaper is each pen?

2. Xiaohua buys popsicles, each 8 yuan 10, Xiaohua 96 * * *. How much will it cost?

3. Buy 50 footballs and get 5 free 1. How much is each 25 yuan actually worth?

4, a box of pure milk 3 yuan money, buy 6 boxes to get 1 box, buy 6 boxes at a time, how much cheaper is each box? How much does it cost to buy a box of * * * for 42 students? How many boxes did you actually buy?

There are two ways to sell toothbrushes in the supermarket. Compare, which is more cost-effective?

Type a and type b

Buy 3 boxes for free 1 box * * 15.6 yuan, buy 1 box for free/box for free * * 8.3 yuan.

6. The price of toothbrush A is 5 PCs 13.5 yuan, and the price of toothbrush B is 17.5 yuan. Which toothbrush is cheaper? How much cheaper is each?