Solution: intersection c is ce∨ad, intersection c is e, intersection c is cf ⊥ AB, intersection c is f, ∫ce∨ad, ab∨CD,

∴ Quadrilateral AECD is a parallelogram,

∴AE=CD=50m,EB=AB-AE=50m，

∠CEB=∠DAB=30，

And ∵ ∠ CBF = 60, so ∠ ECB = 30, ∴CB=EB=50m,

In Rt△CFB, cf = CBS in ∠ 60 = 50× 32 = 253.

A: The distance between Riverbank A and Highway B is 253 meters. ..