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Senior one mathematics trigonometric function examination questions.
From the highest point and the lowest point, there are ωω/ 12+φ=π/2①.

7ωω/ 12+φ= 3π/2②ω=2 Substitute ω= 2 from ②-① into ① φ= π/3.

From the highest point and the lowest point, A+B=3③.

-A+B =-54③+④ to get B=- 1, A=4.

y=4sin(2x+ π/3)- 1

Amplitude A=4 Frequency f=ω/2π=2/2π= 1/π Initial phase φ= π/3.