x+(x+ 1)[-(x+ 1)+ 1]≤ 1

x-(x*2)- 1-2x+x≤0

The square of x+1≥0 x belongs to R, so X.

2.x≥- 1

The square of X+x+1+2x-x-2≤0.

The square of x +2x- 1≤0

-1- radical number 2≤x≤- 1+ radical number 2, so-1≤x≤- 1+ radical number 2.

Because the relationship between yes and no only satisfies any one, and because-1

So x ≤ root number 2- 1