So BE//DF, angle AEB= angle CFD=90 degrees,
Because the quadrilateral ABCD is a parallelogram,
So AD//BC, AD=BC,
So angle ACD= angle CAB,
Because angle AEB= angle CFD=90 degrees, angle ACD= angle CAB, AD=BC,
So the triangle ABE is equal to the triangle CDF(A, a, s),
So BE=DF,
Because BE=DF, BE//DF,
So the quadrangle BEDF is a parallelogram.
16. it is known that in quadrilateral ABCD, AD//BC, angle B+ angle C= 180 degrees,
It is proved that the quadrilateral ABCD is a parallelogram
It is proved that because angle B+ angle C= 180 degrees,
So AB//DC,
Because from AD 100 to BC 100, DC,
So the quadrilateral ABCD is a parallelogram.
17. Guess: EF and GH are equally divided.
It is proved that because the quadrilateral ABCD is a parallelogram,
So AD//BC, AD=BC,
Because AD=BC, AE=FC,
So ED=BF,
Because AD//BC, AE=FC = fc,
The quadrilateral AFCE is a parallelogram,
So AF//EC,
Because AD//BC, ED=BF = BF,
The quadrilateral BFDE is a parallelogram,
So BE//FD,
Because AF//EC, BE//FD,
The quadrilateral EGFH is a parallelogram,
So EF and GH are equally divided.