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The process of solving mathematical parallelogram geometry problems in the second volume of the second day of junior high school! ! !
Because E and D are the midpoint, AB=2AE AC=2AD, and because angle A is equal to angle A, the triangular AED is similar to ABC.

So BC=2ED angle AED=ABC, so ED is parallel to BC.

Similarly, the triangle GMN is similar to GBC, and BC=2MN MN is parallel to BC.

To sum up, BC=2ED BC=2MN is ED=MN.

ED is parallel to BC and MN is parallel to BC, that is, ED is parallel to Mn.

So EDNM is a parallelogram.

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