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20 17 national two-volume mathematics, why does the circled part of the answer account for -2 times of e?
Find a number x close to 0, and h(x) should be greater than 0.

H(x) contains lnx, and you can use a certain power of e to go to ln.

You can try the negative power of e, and h (the negative power of e) is less than 0.

The negative linear term of e is not close to 0, so taking the negative quadratic term of e, it is easy to get that H (negative quadratic term of e) is greater than 0.

If we take h(0.0 1), because there is ln, it is difficult to know the positive and negative. Unless you have a calculator, it is impossible to bring it to the second volume of the country.