Let AB=x and MQ=x/2.

So 3/2x=BX/BM=x-2/x x=8.

2. Take the high line after crossing A, and let ah = xbh = ybd = z.

Countable y 2+x 2 = 2

(x+z)^2+y^2=6

(2z+x)^2+y^2=26

Then solve y

Get two angles by sine

As long as you separate the formula you want, the denominator can be decomposed. Do the math yourself.

1, crossing m is AB parallel MQ.

Let AB=x and MQ=x/2.

So 3/2x=BX/BM=x-2/x x=8.

2. Take the high line after crossing A, and let ah = x BH = y BD = z..

Countable y 2+x 2 = 2

(x+z)^2+y^2=6

(2z+x)^2+y^2=26

Then solve y

Get two angles by sine

As long as you separate the formula you want, the denominator can be decomposed. Do the math yourself.