Let AB=x and MQ=x/2.
So 3/2x=BX/BM=x-2/x x=8.
2. Take the high line after crossing A, and let ah = xbh = ybd = z.
Countable y 2+x 2 = 2
(x+z)^2+y^2=6
(2z+x)^2+y^2=26
Then solve y
Get two angles by sine
As long as you separate the formula you want, the denominator can be decomposed. Do the math yourself.
1, crossing m is AB parallel MQ.
Let AB=x and MQ=x/2.
So 3/2x=BX/BM=x-2/x x=8.
2. Take the high line after crossing A, and let ah = x BH = y BD = z..
Countable y 2+x 2 = 2
(x+z)^2+y^2=6
(2z+x)^2+y^2=26
Then solve y
Get two angles by sine
As long as you separate the formula you want, the denominator can be decomposed. Do the math yourself.