① The downward speed of the two ships is 32km/h, and the upward speed is 28km/h;

(2) Because A is upstream of B, A starts from A and travels downstream, and returns to countercurrent from C; B starts from location b and marches up from location c;

(3) Both ships sailed to C and returned, and B arrived at C 0.5h earlier than A, so C was close to B;

(4) If Party A is in D and Party B is in C (D is between A and C), then when Party B returns to B from C, the whole journey of Party A is actually from D "-C-"D "-A; ;

⑤ The distance from A to B is the sum of the distances from A to C and from B to C;

Solution: If it takes x h for the second ship to reach C first, then the distance that the second ship travels from C to B is 28x km, and the distance that the first ship travels back to A is 32(x+0.5×2), then

28x/32+1.5 = 32 (x+0.5× 2)/28, and the solution is x = 4/3;

So the distance between A and B is 28x+32(x+0.5)=96km.

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