Let AE=X, then de = 2-X.

AB 2+AE 2 = BE 2 is in the triangle ABE.

1^2+X^2=(2-X)^2

X=3/4=0.75

△ABD?△ABM = & gt； △ABE?△MED

s△MED =( 1/2)*(3/4)* 1 = 3/8

2)BM=2

sin∠mbd= 1/√( 1^2+2^2)= 1/√5=>； sin2∠MBD=4/5=0.8

cos2∠MBD=3/5=0.6

So m ordinate 2*0.8= 1.6.

Abscissa 2*0.6= 1.2

2) Solution 2:

AE = EM = 0.75 = & gtBE=DE= 1.25

The height of s △ med =1* 0.75/1.25 = 0.6.

So m ordinate = 1+0.6= 1.6.