Method 1: each person has five, so there are two more.

The second method: if everyone is divided into seven parts, there will be two less.

Method 1: Other children get five apples each, and the last child gets five apples and two more. These apples were given to other children, and the last child got seven apples.

The second method: other children get 7 apples each, and the last child can only get 5 apples.

1 score: 5 for other children and 7 for the last child.

The second method: the other children have seven children each, and the last child has five children.

Method 1: 7 apples of the last child plus 5 apples of any child are equal to 12. Except these two children, each of the other children gave five apples.

The second method: 5 apples for the last child and 7 apples for any child, which is equal to 12. In addition to these two children, the other children also gave seven apples each.

1 method: These two children have 12 apples, and the other children have 5 apples each.

The second method: these two children have 12 apples, and the other children have 7 apples each.

In these two ways, because the two children get the same number of apples, the remaining children get the same number of apples. If there are children besides these two children, one way is to give five to each child, and the other way is to give seven to each child, so the number of apples is not equal. So there are no children and no apples.

So there are only two children and this 12 apple.