Then the two roots of the equation AX 2+BX+C = 0 are x 1, X 2, and its judgment formula is K.
x 1=(-b+k^0.5)/(2a),x2=(-b-k^0.5)/(2a),
There must
Then the two roots of the equation AX 2+BX+C = 0 are x 1, X 2, and its judgment formula is K.
x 1=(-b+k^0.5)/(2a),x2=(-b-k^0.5)/(2a),
There must be x 1-x2 = k 0.5/a > 0.
If a
In the same way; In a similar way
Then the two roots of the equation AX 2+BX+C = 0 are x 1, X 2, and its judgment formula is K.
x 1=(-b+k^0.5)/(2a),x2=(-b-k^0.5)/(2a),
Then there must be x1-x2 = k0.5/a.
In order to facilitate the analysis of the problem
X1> can be assumed; X2