When we met for the first time, two cars walked an AB, and the car at Station A walked 90 kilometers. Then the bus at Station A should have traveled 3×90=270 kilometers. In fact, the bus from Station A took an AB plus (1-65℅)=35℅ AB.

So the distance between AB stations is equal to: 270÷( 1+35℅)=200 (km).