At △ACK and △BPK,

∠AKC=∠PKB (equal to the vertex angle),

So ∠P+∠3=∠ 1+∠C,

That is, ∠P=∠ 1-∠3+∠C, (formula 1)

Let AD and BP intersect at f,

Similarly, ∠P=∠4-∠2+∠D, (Formula 2).

Because ∠ 1=∠2, ∠3=∠4.

Equation 1+ Equation 2,

2∠P=∠C+∠D=32 +28 =60，

Therefore ∠ p = 30.