10 yuan bought five bottles. After drinking them, there were five caps and five empty bottles.

Three bottles of wine use four caps and four empty bottles. After drinking, there are 4 bottle caps and 4 empty bottles left.

Three bottles of wine use four caps and four empty bottles. After drinking, there are 3 bottle caps and 3 empty bottles left.

Exchange 2 empty bottles for 1 bottle of wine. After drinking, there are 4 bottle caps and 2 empty bottles left.

Four bottle caps, two empty bottles for two bottles of wine, and after drinking, there are two bottle caps and two empty bottles left.

Replace 2 empty bottles with 1 bottle of wine. There are 3 bottle caps after drinking, 1 empty bottle.

So * * * can drink 5+3+3+1+2+1=15 bottles.

Extended data:

This kind of problem belongs to the problem of changing empty bottles for wine in mathematics.

Changing empty bottles for wine, also called changing empty bottles for water, is an interesting problem in mathematical operation. It comes from a promotion activity of fully recycling beer bottles by merchants and frequently appears in various exams.

This kind of question is not difficult as a whole, and candidates can easily score. It introduces an easy-to-operate problem-solving skill for candidates.

There is often a saying in the stem of this kind of problem that m empty bottles are replaced by n bottles of water, and we usually convert them into 1 bottle to operate how much water, which will facilitate the problem solving.

For example, if four empty bottles are replaced by 1 bottle of water, there are four bottles = 1 bottle+1 bottle of water (no bottle of water), and 1 bottle = 1/3 bottles of water are introduced. If someone has an empty bottle of 15, he can drink 15 ×.