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Math problem: A pair of robbers and a pair of dogs walk in pairs, with 360 heads and 890 legs. How many robbers and dogs?
Let the number of robbers be x and the number of dogs be y, and the following formula is obtained:
X+Y=360 (robbers and dogs have the same head, so the total is 360).
2X+4Y=890 (robber has 2 legs and dog has 4 legs, so the total number of legs is 890).