AC times DG, s triangle AEC= 1/2.
AC times EH, so DG=EH. Because DG is parallel to EH, the quadrilateral DGHE is a parallelogram, because DE is parallel to AC and DE is not equal to AC, so the quadrilateral ADEC is a trapezoid, and because AD=CE, the quadrilateral AC and DE are isosceles trapezoid.
2. In RT triangle ACD, AC=5, because S triangle ADC= 1/2.
Advertising time CD= 1/2
AC times DG, that is, 1/2 times 3 times 4= 1/2 times 5 times DG, so DG= 12/5. In the RT triangle ADG, AG=9/5, so CH=AG=9/5, so GH=AC-AG-CH=5.
-
9/5
-
9/5
=
7/5, because DEHG is a parallelogram, so DE=GH=7/5, so the perimeter of trapezoidal ACED is AD+AC+EC+DE=3+5+3+.
7/5
=
62/5, so S trapezoid ACED= 1/2(DE+AC) times DG= 1/2.
Multiply (7/5+5) by 12/5.
= 192/25
I am exhausted.