The second pattern has black and white floor tiles ***32=9, including five black brick tiles.

The third pattern has black and white floor tiles ***52=25, of which the black one has 13.

…

The nth pattern has a black and white floor tile ***(2n- 1)2, in which the black half is multiplied by [(2n- 1)2+ 1].

When n= 14, half of the number of black floor tiles is multiplied by [(2×14-1) 2+1] = half× 730 = 365.

So the answer is: 365.

Observing the figure, we can know that the sum of the number of black and white cards is the square of consecutive odd numbers, and the black cards are more than the white cards 1. Find the sum of black and white tiles in the nth pattern, then find the number of black tiles, and then substitute n= 14 for calculation.