It is found that numbers are constantly surrounded by squares, so the law is on the diagonal: 1, 3,7, 13. ......
Plus two, four, six ... are even numbers.
In 2008, in the nth column (row),
Then 1+2+4+...+2 * (n- 1) is greater than 2008.
1+2+4+...+2 * (n-2) is less than 2008
The solution is feasible.
Method 2:
Pay attention to the position of the square.
Because 4= 1+3
9= 1+3+5
16= 1+3+5+7
.......
All squares are in the first row or column.
Because the square of 45 2 > 2008 & gt44 2 45 is 2025-2008 = 17.