(2)x=-2
(3) The intercept on the Y axis is 7, and because k=-4 and y=-4x-7.
(4) According to AB, if two equations are set to calculate kb, you can get y+ 10/3x-34/3.
(5) y=2 or y=-2 because the intercept on the y axis is 2, which is parallel to the x axis.
(6) Get two points from the intercept of xy. For (0, -3) and (4, 0), x/4-y/3- 1=0.
Second, the * * * line; KAB= 1, KBC= 1, so KAB=KBC, and there is a common point b, so ABC has a three-point * * * line. Or we can first find out the equation of the straight line where the two points are located and substitute it into the third point for verification.
Third, let a straight line be L 1. Because L 1 is perpendicular to AB and K 1×KAB=- 1, K 1 is equal to 12/ 10. According to the coordinates of A and B, the midpoint coordinate of AB is (1, 65440.
I am a junior college student. Can I avoid taking some?
Seven situations can be exempted from self-examination.
The first type: Candidates